Unit 8 · Acids & Bases
Lesson 80 of 91

8.9 Henderson–Hasselbalch Equation

01Buffer pH in one line

pH = pKa + log([A⁻]/[HA]). Mole ratio works too since volume cancels.

Ratio 10:1 → pH = pKa + 1; 1:10 → pKa − 1.

02Notebook box

Use moles after any reaction with strong acid/base.

Worked example: pKa 4.74, 0.20 mol A⁻, 0.10 mol HA → pH = 4.74 + log 2 = 5.04.

Key takeaways
  • ✦Ratio inside the log.
  • ✦Moles OK.
  • ✦Only for buffers.
Quick check

Did it stick?

1.pKa 5, [A⁻]/[HA] = 10. pH?

2.To make a pH 7.2 buffer, pick an acid with pKa near…

3.pKa 9.25, equal moles. pH?