Unit 4 · Chemical Reactions
Lesson 33 of 91

4.5 Stoichiometry

01Grams → moles → moles → grams

Convert to moles, use the coefficient ratio, convert back. Find the limiting reactant by seeing which produces less product.

Percent yield = actual ÷ theoretical × 100.

02Notebook box

g A → mol A → (ratio) → mol B → g B.

Worked example: 4.0 g H₂ with excess O₂ → 2 mol H₂ → 2 mol H₂O → 36 g H₂O.

Key takeaways
  • ✦Mole ratio is the bridge.
  • ✦Limiting gives less product.
  • ✦Yield can't exceed 100% legitimately.
Quick check

Did it stick?

1.N₂ + 3H₂ → 2NH₃. Moles NH₃ from 6 mol H₂?

2.Theoretical 10 g, actual 8 g. Yield?

3.Yield over 100% usually means…