Unit 6 · Thermodynamics
Lesson 52 of 91

6.4 Heat Capacity & Calorimetry

01q = mcΔT

Specific heat (c) is the energy to raise 1 g by 1 °C. Water's c = 4.18 J/(g·°C) is high.

In a coffee-cup calorimeter, q_reaction = −q_solution. Divide by moles to get ΔH in kJ/mol.

02Notebook box

q = mcΔT; ΔH = −q_soln / n.

Worked example: 100 g solution warms 5.0 °C → q = 100 × 4.18 × 5 = 2090 J. From 0.050 mol → ΔH = −41.8 kJ/mol.

Key takeaways
  • ✦High c = resists T change.
  • ✦Sign flips between solution and reaction.
  • ✦Per mole for ΔH.
Quick check

Did it stick?

1.Energy to heat 50 g water by 2 °C?

2.Heat lost to the cup makes the measured |ΔH|…

3.Which warms fastest with equal heat & mass?