Unit 7 · Natural Selection
Lesson 50 of 65

7.5 Hardy-Weinberg Equilibrium

01The null hypothesis of evolution

A population is not evolving if five conditions hold: large population, no migration, no mutation, random mating, no selection. Then allele and genotype frequencies stay constant.

Real populations rarely meet all five, so H-W is a baseline to detect evolution.

02The equations

p + q = 1 (allele frequencies). p² + 2pq + q² = 1 (genotype frequencies: AA, Aa, aa).

Start from q² = frequency of recessive phenotype, take the square root to get q.

03Notebook box

Worked example: 16% of a population shows the recessive trait. q² = 0.16 → q = 0.4 → p = 0.6. Heterozygotes = 2pq = 2(0.6)(0.4) = 0.48.

Five conditions: big, isolated, no mutation, random mating, no selection.

Key takeaways
  • ✦p + q = 1; p² + 2pq + q² = 1.
  • ✦Start from q² (recessive phenotype).
  • ✦H-W = no evolution baseline.
Watch outNever start with p² from the dominant phenotype — dominant includes heterozygotes.
Quick check

Did it stick?

1.If q = 0.3, the frequency of heterozygotes is…

2.Which violates H-W?

3.9% of people are homozygous recessive. q =