Unit 5 · Heredity
Lesson 34 of 65

5.3 Mendelian Genetics

01Mendel's laws

Law of segregation: each organism has two alleles per gene, which separate into different gametes. Law of independent assortment: alleles of different genes (on different chromosomes) are sorted independently.

Dominant alleles mask recessive ones. Genotype = allele combination (Aa); phenotype = observable trait.

02Crosses and probability

Monohybrid Aa × Aa → 3:1 phenotype, 1:2:1 genotype. Dihybrid AaBb × AaBb → 9:3:3:1. A testcross with a homozygous recessive reveals an unknown genotype.

Rules of probability: multiply for 'and' (independent events), add for 'or' (mutually exclusive).

03Pedigrees and chi-square

Autosomal recessive traits skip generations; autosomal dominant traits appear in every generation with affected parents.

Chi-square: χ² = Σ (o − e)² / e. Compare to the critical value (df = categories − 1; p = 0.05). If χ² exceeds it, reject the null hypothesis.

04Notebook box

Worked example: AaBbCc × AaBbCc. Probability of aabbcc? → (1/4)(1/4)(1/4) = 1/64.

Critical values (p = 0.05): df 1 = 3.84, df 2 = 5.99, df 3 = 7.81.

Key takeaways
  • ✦Segregation + independent assortment.
  • ✦3:1 and 9:3:3:1 ratios.
  • ✦Multiply for 'and', add for 'or'.
Watch outOn chi-square, 'fail to reject' is correct language — never 'accept the null as true'.
Quick check

Did it stick?

1.Aa × Aa gives what fraction aa?

2.A dihybrid cross of heterozygotes gives a phenotypic ratio of…

3.χ² = 5.2 with 1 df. At p = 0.05 you…